1792 United States presidential election in Pennsylvania

Summary

The 1792 United States presidential election in Pennsylvania took place as part of the 1792 United States presidential election. Pennsylvania voters chose 15 members of the Electoral College,[1] each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

1792 United States presidential election in Pennsylvania

← 1788–89 November 2, 1792 - December 5, 1792 1796 →
 
Nominee George Washington John Adams George Clinton
Party Independent Federalist Democratic-Republican
Home state Virginia Massachusetts New York
Electoral vote 15 14 1
Popular vote 4,576
Percentage 100.00%

President before election

George Washington
Independent

Elected President

George Washington
Independent

Pennsylvania unanimously voted for nonpartisan candidate and incumbent President George Washington. The total statewide popular vote comprised 3,479 for Federalist electors and 1,097 for Anti-Federalist electors, all of whom were supportive of Washington and all but one of whom supported John Adams, the incumbent Vice President; one elector voted for George Clinton.[2]

Results edit

1792 United States presidential election in Pennsylvania[2]
Party Candidate Votes Percentage Electoral votes
Independent George Washington 4,576 100.00% 15
Totals 4,576 100.00% 15

See also edit

References edit

  1. ^ "1792 ELECTION FOR THE SECOND TERM, 1793-1797". National Archives. Retrieved August 4, 2012.
  2. ^ a b "PA US President". Our Campaigns. Retrieved August 4, 2012.