1796 Pennsylvania gubernatorial election

Summary

The 1796 Pennsylvania gubernatorial election occurred on October 11, 1796. Incumbent Democratic-Republican governor Thomas Mifflin successfully sought re-election to a third term. For the second consecutive election, he was victorious over U.S. Representative Frederick Muhlenberg, the Federalist candidate, by a wide margin.

1796 Pennsylvania gubernatorial election

← 1793 October 11, 1796 (1796-10-11)[1] 1799 →
 
Nominee Thomas Mifflin Frederick Muhlenberg
Party Democratic-Republican Federalist
Popular vote 30,020 1,011
Percentage 96.3% 3.2%

County Results
Mifflin:      70-80%      80-90%      90-100%

Governor before election

Thomas Mifflin
Democratic-Republican

Elected Governor

Thomas Mifflin
Democratic-Republican

Results edit

Pennsylvania gubernatorial election, 1796[2][3]
Party Candidate Votes %
Democratic-Republican Thomas Mifflin (incumbent) 30,020 96.31
Federalist Frederick Muhlenberg 1,011 3.24
Federalist Anthony Wayne 139 0.45
Total votes 31,170 100.00

References edit

  1. ^ "Public Notice is Hereby Given". Gazette of the United States, and Philadelphia daily advertiser. Philadelphia, Pa. October 8, 1796. p. 1. Retrieved December 12, 2022.
  2. ^ "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
  3. ^ "Pennsylvania Gubernatorial Election Returns 1796". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.