1812 United States presidential election in Ohio

Summary

The 1812 United States presidential election in Ohio took place as part of the 1812 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.

1812 United States presidential election in Ohio

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Nominee James Madison DeWitt Clinton
Party Democratic-Republican Democratic-Republican[Note 1]
Alliance Federalist
Home state Virginia New York
Running mate Elbridge Gerry Jared Ingersoll
Electoral vote 8 0
Popular vote 7,420 3,301
Percentage 69.21% 30.79%

President before election

James Madison
Democratic-Republican

Elected President

James Madison
Democratic-Republican

Ohio re-elected incumbent Democratic-Republican President James Madison over Federalist candidate DeWitt Clinton. Madison won Ohio by a margin of 38.42%.

Results edit

1816 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican James Madison (incumbent) 7,420 69.21% 8
Federalist DeWitt Clinton 3,301 30.79% 0
Totals 10,721 100.0% 8

See also edit

Notes edit

  1. ^ While commonly labeled as the Federalist candidate, Clinton technically ran as a Democratic-Republican and was not nominated by the Federalist party itself, the latter simply deciding not to field a candidate. This did not prevent endorsements from state Federalist parties (such as in Pennsylvania), but he received the endorsement from the New York state Democratic-Republicans as well

References edit

  1. ^ Ohio. Secretary of State. (1909). Ohio election statistics: the general election. Springfield, Ohio: The Springfield Publishing Company, State Printers. p. 3. OCLC 5470967. Retrieved December 8, 2019.