1826 Pennsylvania gubernatorial election

Summary

The 1826 Pennsylvania gubernatorial election occurred on October 10, 1826. Incumbent governor, John Andrew Shulze, defeated Federalist candidate John Sergeant by a wide margin.

1826 Pennsylvania gubernatorial election

← 1823 October 10, 1826 (1826-10-10) 1829 →
 
Nominee John Andrew Shulze
Party Jacksonian
Popular vote 72,710
Percentage 96.9%

County Results
Shulze:      60-70%      70-80%      80-90%      90-100%
Sergeant:      50-60%

Governor before election

John Andrew Shulze
Democratic

Elected Governor

John Andrew Shulze
Democratic

Results edit

Pennsylvania gubernatorial election, 1826[1]
Party Candidate Votes %
Jacksonian John Andrew Shulze (incumbent) 72,710 96.87
Federalist John Sergeant 1,175 1.57
N/A Others 1,174 1.56
Total votes 75,059 100.00

References edit

  1. ^ "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.