The 1832 United States presidential election in Ohio took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.

1832 United States presidential election in Ohio

← 1828 November 2 – December 5, 1832 1836 →

Nominee Andrew Jackson Henry Clay Party Democratic National Republican Alliance Anti-Masonic Home state Tennessee Kentucky Running mate Martin Van Buren John Sergeant Electoral vote 21 0 Popular vote 81,246 76,539 Percentage 51.33% 48.35%

County Results Jackson   50-60%   60-70%   70-80%   80–90% Clay   50-60%   60-70%   70–80% No Votes   No data

President before election Andrew Jackson Democratic Elected President Andrew Jackson Democratic

Andrew Jackson was the incumbent president running for re-election on the Democratic ticket. Following the result of the 1828 election, the Adams Party split into competing factions. The Anti-Masonic Party drew support from New Englanders in the Western Reserve, while the National Republicans dominated the Anti-Jacksonian opposition in the rest of the state. The Anti-Masons were the first to hold a national convention and nominated former United States Attorney General William Wirt for president. They hoped the selection of Wirt, who had served in the John Quincy Adams Administration, could united all Anti-Jacksonians under a single banner, but the National Republican convention spurned the Anti-Masons and nominated their own candidate, Senator Henry Clay of Kentucky. Fearing a split in the opposition vote could throw the election to Jackson, opposition leaders in Ohio agreed to support a fusion ticket of electors jointly nominated by the two parties who were pledged to vote for whichever candidate stood the best chance to defeat Jackson. While the plan succeeded in nearly uniting Ohio's Anti-Jacksonians, Jackson carried Ohio by a margin of 3 percent.^[1]