1836 United States presidential election in Illinois

Summary

The 1836 United States presidential election in Illinois took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Illinois

← 1832 November 3 – December 7, 1836 1840 →
 
Nominee Martin Van Buren William Henry Harrison
Party Democratic Whig
Home state New York Ohio
Running mate Richard Johnson Francis Granger
Electoral vote 5 0
Popular vote 18,369 15,220
Percentage 54.69% 45.31%

Illinois voted for the Democratic candidate, Martin Van Buren, over Whig candidate William Henry Harrison. Van Buren won Illinois by a margin of 9.38%. This is the last time Ogle County voted Democratic.

Results edit

1836 United States presidential election in Illinois[1]
Party Candidate Votes Percentage Electoral votes
Democratic Martin Van Buren 18,369 54.69% 5
Whig William Henry Harrison 15,220 45.31% 0
Totals 33,589 100.0% 5

See also edit

References edit

  1. ^ "1836 Presidential General Election Results - Illinois". U.S. Election Atlas. Retrieved August 4, 2012.