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1836 United States presidential election in Massachusetts

Summary

The 1836 United States presidential election in Massachusetts took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Massachusetts
← 1832 November 3 – December 7, 1836 1840 →
Turnout43.4%[1] Increase 4.0 pp
 
Nominee Daniel Webster Martin Van Buren
Party Whig Democratic
Home state Massachusetts New York
Running mate Francis Granger Richard Johnson
Electoral vote 14 0
Popular vote 41,201 33,486
Percentage 55.13% 44.81%
County Results

Massachusetts voted for Whig candidate and state native Daniel Webster over the Democratic candidate, Martin Van Buren. Webster won Massachusetts by a margin of 10.32%.

In a unique strategy to throw the election into the house of representatives, the Whigs ran four different candidates in different sections of the United States. This is the only state in which Daniel Webster was on the ballot.[2]

Results edit

1836 United States presidential election in Massachusetts[3]
Party Candidate Votes Percentage Electoral votes
Whig Daniel Webster 41,201 55.13% 14
Democratic Martin Van Buren 33,486 44.81% 0
N/A Other 45 0.06% 0
Totals 74,732 100.0% 14

See also edit

References edit

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "Presidential Election of 1836 - 270toWin". 270toWin.com. Retrieved August 4, 2022.
  3. ^ "1836 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved August 4, 2012.