1845 United States Senate special election in Pennsylvania

Summary

The 1845 United States Senate special election in Pennsylvania was held on March 13, 1845. Simon Cameron was elected by the Pennsylvania General Assembly to the United States Senate.[1]

Background edit

Democrat and future President of the United States James Buchanan was elected to the United States Senate by the Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, in an 1834 special election and was re-elected in 1836 and 1843. Sen. Buchanan resigned on March 5, 1845, after being appointed U.S. Secretary of State by President James K. Polk.[2]

Results edit

Following the resignation of Sen. Buchanan, the Pennsylvania General Assembly convened on March 13, 1845, to elect a new Senator to fill the vacancy and serve the remainder of the term set to expire on March 4, 1849. Five ballots were recorded. The results of the fifth and final ballot of both houses combined are as follows:

State Legislature Results[1]
Party Candidate Votes %
Democratic Simon Cameron 67 50.38
Democratic George W. Woodward 55 41.35
Whig J. R. Ingersoll 2 1.50
Whig John Banks 1 0.75
Know Nothing Peter A. Brown 1 0.75
Unknown Thomas S. Bell 1 0.75
Whig T. D. Cochran 1 0.75
N/A Not voting 5 3.76
Totals 133 100.00%

See also edit

References edit

  1. ^ a b "U.S. Senate Election - 13 March 1845" (PDF). Wilkes University. Retrieved December 22, 2013.
  2. ^ "BUCHANAN, James, (1791 - 1868)". Biographical Directory of the United States Congress. Retrieved December 22, 2013.

External links edit

Preceded by Pennsylvania U.S. Senate election (Class III)
1845
Succeeded by