1856 United States presidential election in Georgia

Summary

The 1856 United States presidential election in Georgia took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for president and vice president.

1856 United States presidential election in Georgia

← 1852 November 4, 1856 1860 →
 
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 10 0
Popular vote 56,581 42,439
Percentage 57.14% 42.86%

County Results

President before election

Franklin Pierce
Democratic

Elected President

James Buchanan
Democratic

Georgia voted for the Democratic candidate, James Buchanan, over American Party candidate Millard Fillmore. Buchanan won Georgia by a margin of 14.28%.

Republican Party candidate John C. Frémont was not on the ballot in the state.

Results edit

1856 United States presidential election in Georgia[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic James Buchanan of Pennsylvania John C. Breckinridge of Kentucky 56,581 57.14% 10 100.00%
Know Nothing Millard Fillmore of New York Andrew Jackson Donelson of Tennessee 42,439 42.86% 0 0.00%
Total 99,020 100.00% 10 100.00%

References edit

  1. ^ "1856 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved December 3, 2017.
  2. ^ "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved December 3, 2017.