1856 United States presidential election in Pennsylvania


1856 United States presidential election in Pennsylvania

← 1852 November 4, 1856 1860 →
  James Buchanan, U.S. Secretary of State.jpg John Charles Fremont crop.jpg Millard Fillmore by Brady Studio 1855-65-crop.jpg
Nominee James Buchanan John C. Frémont Millard Fillmore
Party Democratic Republican Know Nothing
Home state Pennsylvania California New York
Running mate John C. Breckinridge William L. Dayton Andrew Donelson
Electoral vote 27 0 0
Popular vote 230,686 147,286 82,189
Percentage 50.13% 32.01% 17.86%

President before election

Franklin Pierce

Elected President

James Buchanan

The 1856 United States presidential election in Pennsylvania took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose 27 representatives, or electors to the Electoral College, who voted for president and vice president.

Pennsylvania voted for the Democratic candidate, James Buchanan, over the Republican candidate, John C. Frémont, and the Know Nothing candidate, Millard Fillmore. Buchanan, a lifelong Pennsylvanian, won his home state by a margin of 18.12%.

Following the election, Pennsylvania would establish itself as a Republican stronghold. This would be the final time that the Keystone State would vote for a Democratic candidate until Franklin D. Roosevelt won the state in 1936. As of the 2016 presidential election, this is the final time Snyder County voted for a Democratic presidential candidate.[1]


1856 United States presidential election in Pennsylvania[2]
Party Candidate Votes Percentage Electoral votes
Democratic James Buchanan 230,686 50.13% 27
Republican John C. Frémont 147,286 32.01% 0
Know Nothing Millard Fillmore 82,189 17.86% 0
Totals 460,161 100.0% 27


  1. ^ Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 286-290 ISBN 0786422173
  2. ^ "1856 Presidential General Election Results – Pennsylvania". U.S. Election Atlas. Retrieved 3 August 2012.