1860_United_States_presidential_election_in_Maine Knowpia

1860 United States presidential election in Maine
County Results Lincoln 50–60% 60-70% 70-80%
President before election; James Buchanan; Democratic	Elected President ; Abraham Lincoln; Republican

The 1860 United States presidential election in Maine took place on November 2, 1860, as part of the 1860 United States presidential election. Voters chose eight electors of the Electoral College, who voted for president and vice president.

Maine was won by Republican candidate Abraham Lincoln, who won by a margin of 32.82%.

With 62.24% of the popular vote, Maine would prove to be Lincoln's fourth strongest state in terms of popular vote percentage after Vermont, Minnesota and Massachusetts.^[1]

Results edit

1860 United States presidential election in Maine^[2]
Party		Candidate	Running mate	Popular vote		Electoral vote
Party		Candidate	Running mate	Count	%	Count	%
	Republican	Abraham Lincoln of Illinois	Hannibal Hamlin of Maine	62,811	62.24%	8	100.00%
	Democratic	Stephen A. Douglas of Illinois	Herschel Vespasian Johnson of Georgia	29,693	29.42%	0	0.00%
	Southern Democratic	John Cabell Breckinridge of Kentucky	Joseph Lane of Oregon	6,368	6.31%	0	0.00%
	Constitutional Union	John Bell of Tennessee	Edward Everett of Massachusetts	2,046	2.03%	0	0.00%
Total				100,918	100.00%	8	100.00%

References edit

^ "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
^ "1860 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved March 17, 2015.

[1] "1860 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.

[results-2] "1860 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved March 17, 2015.

[1]

[2]

Summary

Results edit

See also edit

References edit