1864 United States presidential election in Pennsylvania

Summary

The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for president and vice president.

1864 United States presidential election in Pennsylvania

← 1860 November 8, 1864 1868 →
 
Nominee Abraham Lincoln George B. McClellan
Party National Union Democratic
Home state Illinois New Jersey
Running mate Andrew Johnson George H. Pendleton
Electoral vote 26 0
Popular vote 296,391 276,316
Percentage 51.75% 48.25%

County Results

President before election

Abraham Lincoln
Republican

Elected President

Abraham Lincoln
National Union

Pennsylvania voted for the National Union candidate, incumbant Republican President Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate, George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a narrow margin of 3.5%.

Results edit

1864 United States presidential election in Pennsylvania[1]
Party Candidate Votes Percentage Electoral votes
National Union Abraham Lincoln (incumbent) 296,391 51.75% 26
Democratic George B. McClellan 276,316 48.25% 0
Totals 572,707 100.0% 26

See also edit

References edit

  1. ^ "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 3, 2012.