1880 United States presidential election in Illinois

Summary

The 1880 United States presidential election in Illinois took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for president and vice president.

1880 United States presidential election in Illinois

← 1876 November 2, 1880 1884 →
 
Nominee James A. Garfield Winfield S. Hancock
Party Republican Democratic
Home state Ohio Pennsylvania
Running mate Chester A. Arthur William H. English
Electoral vote 21 0
Popular vote 318,036 277,321
Percentage 51.11% 44.56%

County Results

President before election

Rutherford B. Hayes
Republican

Elected President

James A. Garfield
Republican

Illinois voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won the state by a margin of 6.55%.[1]

Results edit

1880 United States presidential election in Illinois[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Abram Garfield of Ohio Chester Alan Arthur of New York 318,036 51.11% 21 100.00%
Democratic Winfield Scott Hancock of Pennsylvania William Hayden English of Indiana 277,321 44.56% 0 0.00%
Greenback James Baird Weaver of Iowa Barzillai Jefferson Chambers of Texas 26,358 4.24% 0 0.00%
Prohibition Neal Dow of Maine Henry Adams Thompson of Ohio 440 0.07% 0 0.00%
Anti-Masonic John Wolcott Phelps of Vermont Samuel Clarke Pomeroy of Kansas 150 0.02% 0 0.00%
Total 622,305 100.00% 21 100.00%

See also edit

References edit

  1. ^ Humanities, National Endowment for the (November 10, 1880). "Chicago daily tribune. [volume] (Chicago, Ill.) 1872-1963, November 10, 1880, Image 2". p. 2. ISSN 2572-9985. Retrieved December 3, 2021.
  2. ^ "1880 Presidential General Election Results - Illinois".