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1884 United States presidential election in Massachusetts 
Summary
The 1884 United States presidential election in Massachusetts took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for president and vice president.
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| Turnout | 69.3%[1]  1.9 pp | ||||||||||||||||||||||||||||||||
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 County Results
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Massachusetts voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 8.03%. Greenback nominee and former Massachusetts governor Benjamin Butler won 8.04% of the vote.
Results edit
| 1884 United States presidential election in Massachusetts[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | James Gillespie Blaine of Maine | John Alexander Logan of Illinois | 146,724 | 48.36% | 14 | 100.00% | ||
| Democratic | Grover Cleveland of New York | Thomas Andrews Hendricks of Indiana | 122,352 | 40.33% | 0 | 0.00% | ||
| Greenback | Benjamin Butler of Massachusetts | Absolom Madden West of Mississippi | 24,382 | 8.04% | 0 | 0.00% | ||
| Prohibition | John Pierce St. John of Kansas | William Daniel of Maryland | 9,923 | 3.26% | 0 | 0.00% | ||
| N/A | Others | Others | 2 | 0.01% | 0 | 0.00% | ||
| Total | 303,383 | 100.00% | 14 | 100.00% | ||||
See also edit
References edit