1906 Minnesota Senate election

Summary

The 1906 Minnesota Senate election was held in the U.S. state of Minnesota on November 6, 1906, to elect members to the Senate of the 35th and 36th Minnesota Legislatures.

1906 Minnesota Senate election

← 1902 November 6, 1906 (1906-11-06) 1910 →

All 63 seats in the Minnesota Senate
32 seats needed for a majority
  Majority party Minority party Third party
 
GOP
DEM
PEO
Party Republican Democratic Populist
Seats won 43 19 1
Seat change Decrease1 Increase2 Increase1
Popular vote 164,351 61,484 3,454
Percentage 69.5% 26.0% 1.5%

The Minnesota Republican Party won a large majority of seats, followed by the Minnesota Democratic Party and the People's Party. The new Legislature convened on January 8, 1907.

31 Republicans and 4 Democrats were uncontested.[1]

Results edit

Summary of the November 6, 1906 Minnesota Senate election results
Party Candidates Votes Seats
No. %
Republican Party 58 164,351 43 69.50
Democratic Party 30 61,484 19 26.00
People's Party 1 3,454 1 1.46
Prohibition Party 2 2,072 0 0.88
Public Ownership Party 3 1,925 0 0.81
Independent 2 3,187 0 1.35
Total 236,473 63 100.00
Source: Minnesota Secretary of State[2]

See also edit

References edit

  1. ^ 1907 Minnesota Legislative Manual. Minnesota Secretary of State. 1907. pp. 493–503.
  2. ^ "Election Results - Minnesota Legislative Reference Library". www.leg.state.mn.us. Retrieved January 7, 2020.