1912 Vermont gubernatorial election

Summary

The 1912 Vermont gubernatorial election took place on September 3, 1912. Incumbent Republican John A. Mead, per the "Mountain Rule",[1] did not run for re-election to a second term as Governor of Vermont. Republican candidate Allen M. Fletcher defeated Democratic candidate Harland B. Howe and Progressive candidate Fraser Metzger to succeed him. Since no candidate won a majority of the popular vote, the election was decided and Fletcher was elected by the Vermont General Assembly in accordance with the state constitution.[2]

1912 Vermont gubernatorial election

← 1910 September 3, 1912 (1912-09-03) 1914 →
 
Candidate Allen M. Fletcher Harland B. Howe Fraser Metzger
Party Republican Democratic Progressive
Popular vote 26,237 20,001 15,629
Percentage 40.5% 30.8% 24.1%

Governor before election

John A. Mead
Republican

Elected Governor

Allen M. Fletcher
Republican

This was the last time until 1986 that none of the gubernatorial candidates received a majority of the vote.[3]

Results edit

1912 Vermont gubernatorial election[2]
Party Candidate Votes % ±%
Republican Allen M. Fletcher 26,237 40.5
Democratic Harland B. Howe 20,001 30.8
Progressive Fraser Metzger 15,629 24.1
Prohibition Clement F. Smith 1,735 2.7
Socialist Fred W. Suitor 1,210 1.9
N/A Other 27 0.0
Total votes '64,839' '100'

References edit

  1. ^ Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved January 1, 2015.
  2. ^ a b "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Archived from the original (PDF) on November 30, 2014. Retrieved January 1, 2015.
  3. ^ Doyle 1992, p. 222.

Works cited edit

  • Doyle, William (1992). The Vermont Political Tradition: And Those Who Helped Make It. ISBN 0961548614.