1930 Rhode Island gubernatorial election

Summary

The 1930 Rhode Island gubernatorial election was held on November 4, 1930. Incumbent Republican Norman S. Case defeated Democratic nominee Theodore F. Green with 50.53% of the vote.

1930 Rhode Island gubernatorial election

← 1928 November 4, 1930 1932 →
 
Nominee Norman S. Case Theodore F. Green
Party Republican Democratic
Popular vote 112,070 108,558
Percentage 50.53% 48.95%

Governor before election

Norman S. Case
Republican

Elected Governor

Norman S. Case
Republican

General election edit

Candidates edit

Major party candidates

  • Norman S. Case, Republican
  • Theodore F. Green, Democratic

Other candidates

  • Charles H. Dana, Socialist

Results edit

1930 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Norman S. Case (incumbent) 112,070 50.53%
Democratic Theodore F. Green 108,558 48.95%
Socialist Charles H. Dana 1,168 0.53%
Majority 3,512
Turnout
Republican hold Swing

References edit

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 7, 2020.