1946 Iowa gubernatorial election

Summary

The 1946 Iowa gubernatorial election was held on November 5, 1946. Incumbent Republican Robert D. Blue defeated Democratic nominee Frank Miles with 57.40% of the vote.

1946 Iowa gubernatorial election

← 1944 November 5, 1946 1948 →
 
Nominee Robert D. Blue Frank Miles
Party Republican Democratic
Popular vote 362,592 266,190
Percentage 57.40% 42.14%

County results

Blue:      40-50%      50-60%      60-70%      70-80%

Miles:      50–60%

Governor before election

Robert D. Blue
Republican

Elected Governor

Robert D. Blue
Republican

Primary elections edit

Primary elections were held on June 3, 1946.[1]

Democratic primary edit

Candidates edit

  • Frank Miles, Editor of the Iowa Legionnaire

Results edit

Democratic primary results[1]
Party Candidate Votes %
Democratic Frank Miles 50,385 100.00
Total votes 50,385 100.00

Republican primary edit

Candidates edit

Results edit

Republican primary results[1]
Party Candidate Votes %
Republican Robert D. Blue (incumbent) 141,024
Republican George H. Olmsted 80,590
Total votes

General election edit

Candidates edit

Major party candidates

  • Robert D. Blue, Republican
  • Frank Miles, Democratic

Other candidates

  • E. P. Gabriel, Prohibition

Results edit

1946 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican Robert D. Blue (incumbent) 362,592 57.40%
Democratic Frank Miles 266,190 42.14%
Prohibition E. P. Gabriel 2,899 0.46%
Majority 96,402
Turnout 631,681
Republican hold Swing

References edit

  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1946. Retrieved April 12, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1946. Retrieved April 12, 2020.