1964 Iowa gubernatorial election

Summary

The 1964 Iowa gubernatorial election was held on November 3, 1964. Incumbent Democrat Harold Hughes defeated Republican nominee Evan Hultman with 68.05% of the vote.

1964 Iowa gubernatorial election

← 1962 November 3, 1964 1966 →
 
Nominee Harold Hughes Evan Hultman
Party Democratic Republican
Popular vote 794,610 365,131
Percentage 68.05% 31.27%

County results
Hughes:      50–60%      60–70%      70–80%
Hultman:      50–60%

Governor before election

Harold Hughes
Democratic

Elected Governor

Harold Hughes
Democratic

Primary elections edit

Primary elections were held on June 1, 1964.[1]

Democratic primary edit

Candidates edit

Results edit

Democratic primary results[1]
Party Candidate Votes %
Democratic Harold Hughes (incumbent) 103,947 100.00
Total votes 103,947 100.00

Republican primary edit

Candidates edit

Results edit

Republican primary results[1]
Party Candidate Votes %
Republican Evan Hultman 163,523 100.00
Total votes 163,523 100.00

General election edit

Candidates edit

Major party candidates

  • Harold Hughes, Democratic
  • Evan Hultman, Republican

Other candidates

  • Robert D. Dilley, Independent

Results edit

1964 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Democratic Harold Hughes (incumbent) 794,610 68.05%
Republican Evan Hultman 365,131 31.27%
Independent Robert D. Dilley 7,985 0.68%
Majority 429,479
Turnout 1,167,734
Democratic hold Swing

References edit

  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1964. Retrieved March 22, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1964. Retrieved March 22, 2020.