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1968 Delaware gubernatorial election 
Summary
The 1968 Delaware gubernatorial election was held on November 5, 1968. Republican nominee Russell W. Peterson defeated incumbent Democratic Governor Charles L. Terry Jr. with 50.51% of the vote.
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 County results Peterson: 50–60% | |||||||||||||||||
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General election edit
Nominations edit
Nominations were made by party conventions.[1][2]
Candidates edit
- Russell W. Peterson, Republican, civic activist
- Charles L. Terry Jr., Democratic, incumbent Governor
Results edit
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Russell W. Peterson | 104,474 | 50.51% | ||
| Democratic | Charles L. Terry Jr. (incumbent) | 102,360 | 49.49% | ||
| Majority | 2,114 | 1.02% | |||
| Turnout | 206,834 | 100.00% | |||
| Republican gain from Democratic | Swing | ||||
References edit
- ^ America Votes 8, p. 62.
- ^ Delaware Official Results 1968, p. 17.
- ^ "DE Governor, 1968". Our Campaigns. Retrieved June 4, 2020.
- ^ America Votes 8, p. 58.
- ^ Delaware Official Results 1968, p. 2.
- ^ Congressional Quarterly 1998, p. 46.
Bibliography edit
- George W. Cripps, Commissioner of Elections (1969). Official Results of General Election, 1968 (PDF). State of Delaware.
- Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
- Scammon, Richard M., ed. (1956). America Votes 8: a handbook of contemporary American election statistics, 1968. Washington, D.C.: Governmental Affairs Institute (published 1970).