1968 United States Senate election in Georgia

Summary

The 1968 United States Senate election in Georgia took place on November 5, 1968. Incumbent Democratic U.S. Senator Herman Talmadge was re-elected to a third consecutive term in office, winning large victories in the primary and general elections.

1968 United States Senate election in Georgia

← 1962 November 5, 1968 1974 →
 
Nominee Herman Talmadge E. Earl Patton
Party Democratic Republican
Popular vote 885,093 246,865
Percentage 77.51% 22.49%

County results
Talmadge:      50–60%      60–70%      70–80%      80–90%      >90%
Patton:      50-60%

U.S. senator before election

Herman Talmadge
Democratic

Elected U.S. Senator

Herman Talmadge
Democratic

For the first time, Republicans held a primary election to nominate a candidate for U.S. Senate.

Democratic primary edit

Candidates edit

Results edit

1968 Democratic U.S. Senate primary results[1]
Party Candidate Votes %
Democratic Herman Talmadge (incumbent) 627,915 75.19%
Democratic Maynard Jackson 207,171 24.81%
Total votes 835,086 100.00%

Republican primary edit

Candidates edit

Results edit

1968 Republican U.S. Senate primary results[2]
Party Candidate Votes %
Republican E. Earl Patton 20,316 59.54%
Republican Jack Sells 13,805 40.46%
Total votes 34,121 100.00%

General election edit

Results edit

1968 United States Senate election in Georgia[3]
Party Candidate Votes % ±%
Democratic Herman Talmadge (incumbent) 885,093 77.51%  22.49
Republican E. Earl Patton 256,796 22.49%  22.49
Total votes 1,141,889 100.00%
Democratic hold Swing

See also edit

References edit

  1. ^ "Our Campaigns - GA US Senate - D Primary Race - Sep 11, 1968".
  2. ^ "Our Campaigns - GA US Senate - R Primary Race - Sep 11, 1968".
  3. ^ "Our Campaigns - GA US Senate Race - Nov 05, 1974".