1990 Rhode Island gubernatorial election

Summary

The 1990 Rhode Island gubernatorial election was held on November 6, 1990. Democratic nominee Bruce Sundlun defeated incumbent Republican Edward D. DiPrete with 74.15% of the vote.

1990 Rhode Island gubernatorial election

← 1988 November 6, 1990 1992 →
 
Nominee Bruce Sundlun Edward D. DiPrete
Party Democratic Republican
Popular vote 264,411 92,177
Percentage 74.15% 25.85%

Sundlun:      60–70%      70–80%      80–90%

Governor before election

Edward D. DiPrete
Republican

Elected Governor

Bruce Sundlun
Democratic

Primary elections edit

Primary elections were held on September 11, 1990.[1]

Democratic primary edit

Candidates edit

Results edit

 
Results by municipality:
Sundlun
  •   Sundlun—30–40%
  •   Sundlun—40–50%
  •   Sundlun—50–60%
Flaherty
  •   Flaherty—30–40%
  •   Flaherty—40–50%
Paolino
  •   Paolino—30–40%
  •   Paolino—40–50%
  •   Paolino—50–60%
Democratic primary results[1]
Party Candidate Votes %
Democratic Bruce Sundlun 68,021 40.51
Democratic Francis X. Flaherty 53,821 32.05
Democratic Joseph R. Paolino Jr. 46,074 27.44
Total votes 167,916 100.00

Republican primary edit

Candidates edit

Results edit

Republican primary results[1]
Party Candidate Votes %
Republican Edward D. DiPrete (incumbent) 7,644 70.77
Republican Steve White 3,157 29.23
Total votes 10,801 100.00

General election edit

Candidates edit

  • Bruce Sundlun, Democratic
  • Edward D. DiPrete, Republican

Results edit

1990 Rhode Island gubernatorial election[1]
Party Candidate Votes %
Democratic Bruce Sundlun 264,411 74.15%
Republican Edward D. DiPrete (incumbent) 92,177 25.85%
Total votes 356,672 100.00%
Democratic gain from Republican

References edit

  1. ^ a b c d "1990 Count Book" (PDF). Secretary of State of Rhode Island. 1990. Archived from the original (PDF) on December 2, 2018. Retrieved November 8, 2018.