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1996 United States House of Representatives elections in Arizona 
Summary
The 1996 congressional elections in Arizona were elections for Arizona's delegation to the United States House of Representatives, which occurred concurrently with congressional elections nationwide on November 5, 1996. Arizona has six seats, as apportioned during the 1990 United States census. Republicans held five seats and Democrats held one seat.
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All 6 Arizona seats to the United States House of Representatives | |||||||||||||||||||||||||
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Overview edit
| 1996 United States House of Representatives elections in Arizona[1] | |||||
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| Party | Votes | Percentage | Seats | +/– | |
| Republican | 800,917 | 59.05% | 5 | - | |
| Democratic | 521,345 | 38.43% | 1 | - | |
| Libertarian | 27,554 | 2.03% | 0 | - | |
| Others | 6,630 | 0.49% | 0 | - | |
| Totals | 1,356,446 | 100.00% | 6 | - | |
References edit
- ^ "Statistics of the Presidential and Congressional Election of November 5, 1996" (PDF). Clerk.house.gov. Retrieved October 13, 2013.