Battle of Bantam

Summary

Battle of Bantam
Part of Dutch-Portuguese War

Victory of the Dutch over the Portuguese fleet in Banten, 1601.
Date27 December 1601
Location
Result Dutch victory
Belligerents
 Dutch Republic Portugal Portuguese Empire
Strength
5 ships 8 galleons
several fustas
Casualties and losses
None 3 fustas captured

The naval Battle of Bantam took place on 27 December 1601 in Bantam Bay (now Banten Bay), Indonesia, when an exploration fleet of five Dutch ships under the command of Wolfert Harmensz and a Portuguese fleet under André Furtado de Mendonça, sent from Goa to restore Portuguese authority, met in the Indonesian archipelago. The battle resulted in Dutch victory and forced the Portuguese to retreat.[1] Netherlands made three ships booty on a large Portuguese force majeure of eight galleons and miscellaneous smaller vessels.

Ships involved edit

  • Netherlands
    • Gelderland (Wolfert Harmensz)
    • Zeelandia (Jan Cornelisz)
    • Utrecht (Jan Martensz)
    • Wachter (yacht) (Gerrit Hendricksz Roobol)
    • Duyfken (yacht) (Willem Schouten)
  • Portugal (André Furtado de Mendonça), 30 vessels total
    • 8 galleons
    • Several fustas—3 set alight and captured by Dutch

References edit

  1. ^ Moree, Perry (2001). Dodo's en Galjoenen. De reis van het schip Gelderland naar Oost-Indië, 1601-1603 [Dodo's and Galleons. The voyage of the ship Gelderland to East-India, 1601-1603] (in Dutch). Waburg Pers. ISBN 9057301717.