${\displaystyle {\begin{pmatrix}A&B\\C&D\end{pmatrix}}={\begin{pmatrix}I&0\\CA^{-1}&I\end{pmatrix}}{\begin{pmatrix}A&0\\0&D-CA^{-1}B\end{pmatrix}}{\begin{pmatrix}I&A^{-1}B\\0&I\end{pmatrix}}}$ 

Consider a block matrix:

${\displaystyle {\begin{pmatrix}A&B\\C&D\end{pmatrix}}={\begin{pmatrix}I\\CA^{-1}\end{pmatrix}}\,A\,{\begin{pmatrix}I&A^{-1}B\end{pmatrix}}+{\begin{pmatrix}0&0\\0&D-CA^{-1}B\end{pmatrix}},}$ 

where the matrix ${\displaystyle {\begin{matrix}A\end{matrix}}}$  is assumed to be non-singular, ${\displaystyle {\begin{matrix}I\end{matrix}}}$  is an identity matrix with proper dimension, and ${\displaystyle {\begin{matrix}0\end{matrix}}}$  is a matrix whose elements are all zero.

We can also rewrite the above equation using the half matrices:

${\displaystyle {\begin{pmatrix}A&B\\C&D\end{pmatrix}}={\begin{pmatrix}A^{\frac {1}{2}}\\CA^{-{\frac {*}{2}}}\end{pmatrix}}{\begin{pmatrix}A^{\frac {*}{2}}&A^{-{\frac {1}{2}}}B\end{pmatrix}}+{\begin{pmatrix}0&0\\0&Q^{\frac {1}{2}}\end{pmatrix}}{\begin{pmatrix}0&0\\0&Q^{\frac {*}{2}}\end{pmatrix}},}$ 

where the Schur complement of ${\displaystyle {\begin{matrix}A\end{matrix}}}$  in the block matrix is defined by

${\displaystyle {\begin{matrix}Q=D-CA^{-1}B\end{matrix}}}$ 

and the half matrices can be calculated by means of Cholesky decomposition or LDL decomposition. The half matrices satisfy that

${\displaystyle {\begin{matrix}A^{\frac {1}{2}}\,A^{\frac {*}{2}}=A;\end{matrix}}\qquad {\begin{matrix}A^{\frac {1}{2}}\,A^{-{\frac {1}{2}}}=I;\end{matrix}}\qquad {\begin{matrix}A^{-{\frac {*}{2}}}\,A^{\frac {*}{2}}=I;\end{matrix}}\qquad {\begin{matrix}Q^{\frac {1}{2}}\,Q^{\frac {*}{2}}=Q.\end{matrix}}}$ 

Thus, we have

${\displaystyle {\begin{pmatrix}A&B\\C&D\end{pmatrix}}=LU,}$ 

where

${\displaystyle LU={\begin{pmatrix}A^{\frac {1}{2}}&0\\CA^{-{\frac {*}{2}}}&0\end{pmatrix}}{\begin{pmatrix}A^{\frac {*}{2}}&A^{-{\frac {1}{2}}}B\\0&0\end{pmatrix}}+{\begin{pmatrix}0&0\\0&Q^{\frac {1}{2}}\end{pmatrix}}{\begin{pmatrix}0&0\\0&Q^{\frac {*}{2}}\end{pmatrix}}.}$ 

The matrix ${\displaystyle {\begin{matrix}LU\end{matrix}}}$  can be decomposed in an algebraic manner into

${\displaystyle L={\begin{pmatrix}A^{\frac {1}{2}}&0\\CA^{-{\frac {*}{2}}}&Q^{\frac {1}{2}}\end{pmatrix}}\mathrm {~~and~~} U={\begin{pmatrix}A^{\frac {*}{2}}&A^{-{\frac {1}{2}}}B\\0&Q^{\frac {*}{2}}\end{pmatrix}}.}$ 

• Matrix decomposition