If is a ring, let denote the ring of polynomials in the indeterminate over . Hilbert proved that if is "not too large", in the sense that if is Noetherian, the same must be true for . Formally,
Hilbert's Basis Theorem. If is a Noetherian ring, then is a Noetherian ring.
Corollary. If is a Noetherian ring, then is a Noetherian ring.
This can be translated into algebraic geometry as follows: every algebraic set over a field can be described as the set of common roots of finitely many polynomial equations. Hilbert proved the theorem (for the special case of polynomial rings over a field) in the course of his proof of finite generation of rings of invariants.
Remark. We will give two proofs, in both only the "left" case is considered; the proof for the right case is similar.
Suppose is a non-finitely generated left ideal. Then by recursion (using the axiom of dependent choice) there is a sequence of polynomials such that if is the left ideal generated by then is of minimal degree. It is clear that is a non-decreasing sequence of natural numbers. Let be the leading coefficient of and let be the left ideal in generated by . Since is Noetherian the chain of ideals
must terminate. Thus for some integer. So in particular,
whose leading term is equal to that of ; moreover, . However, , which means that has degree less than , contradicting the minimality.
Let be a left ideal. Let be the set of leading coefficients of members of . This is obviously a left ideal over , and so is finitely generated by the leading coefficients of finitely many members of ; say . Let be the maximum of the set , and let be the set of leading coefficients of members of , whose degree is . As before, the are left ideals over , and so are finitely generated by the leading coefficients of finitely many members of , say
with degrees . Now let be the left ideal generated by:
We have and claim also . Suppose for the sake of contradiction this is not so. Then let be of minimal degree, and denote its leading coefficient by .
Case 1:. Regardless of this condition, we have , so is a left linear combination
of the coefficients of the . Consider
which has the same leading term as ; moreover while . Therefore and , which contradicts minimality.
Case 2:. Then so is a left linear combination
of the leading coefficients of the . Considering
we yield a similar contradiction as in Case 1.
Thus our claim holds, and which is finitely generated.
Note that the only reason we had to split into two cases was to ensure that the powers of multiplying the factors were non-negative in the constructions.
Since any affine variety over (i.e. a locus-set of a collection of polynomials) may be written as the locus of an ideal and further as the locus of its generators, it follows that every affine variety is the locus of finitely many polynomials — i.e. the intersection of finitely many hypersurfaces.