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Hobart Township, Lake County, Indiana

Summary

Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.[4]

Hobart Township
Township
Coordinates: 41°32′48″N 87°15′53″W / 41.54667°N 87.26472°W / 41.54667; -87.26472
CountryUnited States
StateIndiana
CountyLake
Government
 • TypeIndiana township
Area
 • Total25.98 sq mi (67.3 km2)
 • Land25.47 sq mi (66.0 km2)
 • Water0.51 sq mi (1.3 km2)
Elevation
[1]
627 ft (191 m)
Population
 (2020)[2]
 • Total40,652
 • Density1,547.4/sq mi (597.5/km2)
FIPS code18-34132[3]
GNIS feature ID453414
Historical population
CensusPop.Note%±
18902,197—
19002,71823.7%
19103,72937.2%
19205,62150.7%
19309,13562.5%
194012,47236.5%
195021,87175.4%
196039,22379.3%
197040,8254.1%
198042,5484.2%
199038,942−8.5%
200039,6361.8%
201039,417−0.6%
202040,6523.1%
Source: US Decennial Census[5]

Geography edit

According to the 2010 census, the township has a total area of 25.98 square miles (67.3 km2), of which 25.47 square miles (66.0 km2) (or 98.04%) is land and 0.51 square miles (1.3 km2) (or 1.96%) is water.[4]

References edit

  1. ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
  2. ^ "Census Bureau profile: Hobart Township, Lake County, Indiana". United States Census Bureau. May 2023. Retrieved March 15, 2024.
  3. ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
  4. ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
  5. ^ "Township Census Counts: STATS Indiana".

External links edit

  • Indiana Township Association
  • United Township Association of Indiana