In number theory, quadratic Gauss sums are certain finite sums of roots of unity. A quadratic Gauss sum can be interpreted as a linear combination of the values of the complex exponential function with coefficients given by a quadratic character; for a general character, one obtains a more general Gauss sum. These objects are named after Carl Friedrich Gauss, who studied them extensively and applied them to quadratic, cubic, and biquadratic reciprocity laws.
Definition
edit
For an odd prime numberp and an integer a, the quadratic Gauss sumg(a; p) is defined as
The evaluation of the Gauss sum for an integer a not divisible by a prime p > 2 can be reduced to the case a = 1:
The exact value of the Gauss sum for a = 1 is given by the formula:[1]
Remark
In fact, the identity
was easy to prove and led to one of Gauss's proofs of quadratic reciprocity. However, the determination of the sign of the Gauss sum turned out to be considerably more difficult: Gauss could only establish it after several years' work. Later, Dirichlet, Kronecker, Schur and other mathematicians found different proofs.
Generalized quadratic Gauss sums
edit
Let a, b, c be natural numbers. The generalized quadratic Gauss sumG(a, b, c) is defined by
.
The classical quadratic Gauss sum is the sum g(a, p) = G(a, 0, p).
Properties
The Gauss sum G(a,b,c) depends only on the residue class of a and b modulo c.
Gauss sums are multiplicative, i.e. given natural numbers a, b, c, d with gcd(c, d) = 1 one has
One has G(a, b, c) = 0 if gcd(a, c) > 1 except if gcd(a,c) divides b in which case one has
.
Thus in the evaluation of quadratic Gauss sums one may always assume gcd(a, c) = 1.
Let a, b, c be integers with ac ≠ 0 and ac + b even. One has the following analogue of the quadratic reciprocity law for (even more general) Gauss sums[2]
.
Define
for every odd integer m. The values of Gauss sums with b = 0 and gcd(a, c) = 1 are explicitly given by
For b > 0 the Gauss sums can easily be computed by completing the square in most cases. This fails however in some cases (for example, c even and b odd), which can be computed relatively easy by other means. For example, if c is odd and gcd(a, c) = 1 one has
where ψ(a) is some number with 4ψ(a)a ≡ 1 (mod c). As another example, if 4 divides c and b is odd and as always gcd(a, c) = 1 then G(a, b, c) = 0. This can, for example, be proved as follows: because of the multiplicative property of Gauss sums we only have to show that G(a, b, 2m) = 0 if n > 1 and a, b are odd with gcd(a, c) = 1. If b is odd then an2 + bn is even for all 0 ≤ n < c − 1. For every q, the equation an2 + bn + q = 0 has at most two solutions in /2n. Indeed, if and are two solutions of same parity, then for some integer , but is odd, hence . [clarification needed] Because of a counting argument an2 + bn runs through all even residue classes modulo c exactly two times. The geometric sum formula then shows that G(a, b, 2m) = 0.