1793 Pennsylvania gubernatorial election

Summary

The 1793 Pennsylvania gubernatorial election occurred on October 8, 1793. Incumbent Democratic-Republican governor Thomas Mifflin sought re-election to another term, defeating Federalist candidate and U.S. Representative Frederick Muhlenberg. Muhlenberg won only two counties: York and Bedford. However, Mifflin's 2-1 vote margin was down from his 10-1 victory margin in the 1790 gubernatorial election.[2]

1793 Pennsylvania gubernatorial election

← 1790 October 8, 1793 (1793-10-08)[1] 1796 →
 
Candidate Thomas Mifflin Frederick Muhlenberg
Party Democratic-Republican Federalist
Popular vote 20,479 10,803
Percentage 65.4% 34.5%

County Results


Mifflin:      50-60%      60-70%      70-80%      80-90%      90-100%
Muhlenberg:      50-60%

     60-70%

Governor before election

Thomas Mifflin
Democratic-Republican

Elected Governor

Thomas Mifflin
Democratic-Republican

Results edit

Pennsylvania gubernatorial election, 1793[3][4]
Party Candidate Votes %
Democratic-Republican Thomas Mifflin (incumbent) 20,479 65.43
Federalist Frederick Muhlenberg 10,803 34.51
Independent Alexander McDowell 8 0.03
N/A Others 11 0.04
Total votes 31,301 100.00

References edit

  1. ^ "Article II". Constitution of the Commonwealth of Pennsylvania - 1790 (PDF).
  2. ^ Tinkcom, Harry Marlin. 1950. The Republicans and Federalists in Pennsylvania: 1790-1801. Harrisburg: Pennsylvania Historical and Museum Commission, p. 138
  3. ^ "PA Governor General Election". OurCampaigns. Retrieved July 3, 2012.
  4. ^ "Pennsylvania Gubernatorial Election Returns 1793". House of Representatives of the Commonwealth of Pennsylvania. Retrieved July 3, 2012.