1918 Rhode Island gubernatorial election

Summary

The 1918 Rhode Island gubernatorial election was held on November 5, 1918. Incumbent Republican Robert Livingston Beeckman defeated Democratic nominee Alberic A. Archambault with 53.11% of the vote.

1918 Rhode Island gubernatorial election

← 1916 November 5, 1918 1920 →
 
Nominee Robert Livingston Beeckman Alberic A. Archambault
Party Republican Democratic
Popular vote 42,682 36,031
Percentage 53.11% 44.84%

Governor before election

Robert Livingston Beeckman
Republican

Elected Governor

Robert Livingston Beeckman
Republican

General election edit

Candidates edit

Major party candidates

  • Robert Livingston Beeckman, Republican
  • Alberic A. Archambault, Democratic

Other candidates

  • Ernest Sherwood, Socialist

Results edit

1918 Rhode Island gubernatorial election[1]
Party Candidate Votes % ±%
Republican Robert Livingston Beeckman (incumbent) 42,682 53.11%
Democratic Alberic A. Archambault 36,031 44.84%
Socialist Ernest Sherwood 1,648 2.05%
Majority 6,651
Turnout
Republican hold Swing

References edit

  1. ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 20, 2020.