1956 United States Senate election in Arkansas

Summary

The 1956 United States Senate election in Arkansas took place on November 2, 1956. Incumbent Senator J. William Fulbright won a third term in office. Without a primary challenger to Fulbright, the election did not attract much attention, as the Democratic nomination was tantamount to victory in the South.

1956 U.S. Senate election in Arkansas

← 1950 November 6, 1956 1962 →
 
Nominee J. William Fulbright Ben C. Henley
Party Democratic Republican
Popular vote 331,679 98,013
Percentage 82.98% 17.02%

County results
Fulbright:      50–60%      60–70%      70–80%      80–90%      >90%
Henley:      50–60%

U.S. senator before election

J. William Fulbright
Democratic

Elected U.S. Senator

J. William Fulbright
Democratic

Fulbright defeated Republican Ben Henley in a landslide.

General election edit

Results edit

1956 U.S. Senate election in Arkansas[1][2]
Party Candidate Votes %
Democratic J. William Fulbright (inc.) 331,679 82.98%
Republican Ben C. Henley 68,016 17.02%
Total votes 399,695 100.00%

See also edit

References edit

  1. ^ Arkansas Secretary of State Mark Martin (2018). "Historical Report of the Secretary of State" (PDF). p. 363.
  2. ^ Clerk of the United States House of Representatives (1957). "Statistics of the Congressional Election of November 8', 1956" (PDF). U.S. Government Printing Office.