Let ${\displaystyle x(t)}$  and ${\displaystyle y(t)}$  be the coordinates of the points of the curve expressed as functions of a variable t:

${\displaystyle y=y(t),\quad x=x(t).}$ 

The first derivative implied by these parametric equations is

${\displaystyle {\frac {dy}{dx}}={\frac {dy/dt}{dx/dt}}={\frac {{\dot {y}}(t)}{{\dot {x}}(t)}},}$ 

where the notation ${\displaystyle {\dot {x}}(t)}$  denotes the derivative of x with respect to t. This can be derived using the chain rule for derivatives:

${\displaystyle {\frac {dy}{dt}}={\frac {dy}{dx}}\cdot {\frac {dx}{dt}}}$ 

and dividing both sides by ${\textstyle {\frac {dx}{dt}}}$  to give the equation above.

In general all of these derivatives — dy / dt, dx / dt, and dy / dx — are themselves functions of t and so can be written more explicitly as, for example, ${\displaystyle {\tfrac {dy}{dx}}(t).}$ 

The second derivative implied by a parametric equation is given by

by making use of the quotient rule for derivatives. The latter result is useful in the computation of curvature.

For example, consider the set of functions where:

${\displaystyle x(t)=4t^{2}\,}$ 

and

${\displaystyle y(t)=3t.\,}$ 

Differentiating both functions with respect to t leads to

${\displaystyle {\frac {dx}{dt}}=8t}$ 

and

${\displaystyle {\frac {dy}{dt}}=3,}$ 

respectively. Substituting these into the formula for the parametric derivative, we obtain

${\displaystyle {\frac {dy}{dx}}={\frac {\dot {y}}{\dot {x}}}={\frac {3}{8t}},}$ 

where ${\displaystyle {\dot {x}}}$  and ${\displaystyle {\dot {y}}}$  are understood to be functions of t.

• Generalizations of the derivative

• Derivative for parametric form at PlanetMath.
• Harris, John W. & Stöcker, Horst (1998). "12.2.12 Differentiation of functions in parametric representation". Handbook of Mathematics and Computational Science. Springer Science & Business Media. pp. 495–497. ISBN 0387947469.