Squeeze operator

Summary

In quantum physics, the squeeze operator for a single mode of the electromagnetic field is[1]

where the operators inside the exponential are the ladder operators. It is a unitary operator and therefore obeys , where is the identity operator.

Its action on the annihilation and creation operators produces

The squeeze operator is ubiquitous in quantum optics and can operate on any state. For example, when acting upon the vacuum, the squeezing operator produces the squeezed vacuum state.

The squeezing operator can also act on coherent states and produce squeezed coherent states. The squeezing operator does not commute with the displacement operator:

nor does it commute with the ladder operators, so one must pay close attention to how the operators are used. There is, however, a simple braiding relation, [2]

Application of both operators above on the vacuum produces squeezed coherent states:

.

Derivation of action on creation operator edit

As mentioned above, the action of the squeeze operator   on the annihilation operator   can be written as

 
To derive this equality, let us define the (skew-Hermitian) operator  , so that  .

The left hand side of the equality is thus  . We can now make use of the general equality

 
which holds true for any pair of operators   and  . To compute   thus reduces to the problem of computing the repeated commutators between   and  . As can be readily verified, we have
 
 
Using these equalities, we obtain

 

so that finally we get

 

See also edit

References edit

  1. ^ Gerry, C.C. & Knight, P.L. (2005). Introductory quantum optics. Cambridge University Press. p. 182. ISBN 978-0-521-52735-4.
  2. ^ M. M. Nieto and D. Truax (1995), Nieto, Michael Martin; Truax, D. Rodney (1997). "Holstein‐Primakoff/Bogoliubov Transformations and the Multiboson System". Fortschritte der Physik/Progress of Physics. 45 (2): 145–156. arXiv:quant-ph/9506025. doi:10.1002/prop.2190450204. S2CID 14213781. Eqn (15). Note that in this reference, the definition of the squeeze operator (eqn. 12) differs by a minus sign inside the exponential, therefore the expression of   is modified accordingly ( ).