1944 Iowa gubernatorial election

Summary

The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.

1944 Iowa gubernatorial election

← 1942 November 7, 1944 1946 →
 
Nominee Robert D. Blue Richard F. Mitchell
Party Republican Democratic
Popular vote 561,827 437,684
Percentage 56.01% 43.63%

County results

Blue:      50-60%      60-70%      70-80%

Mitchell:      50-60%

Governor before election

Bourke B. Hickenlooper
Republican

Elected Governor

Robert D. Blue
Republican

Primary elections edit

Primary elections were held on June 5, 1944.[1]

Democratic primary edit

Candidates edit

Results edit

Democratic primary results[1]
Party Candidate Votes %
Democratic Richard F. Mitchell 38,086 100.00
Total votes 38,086 100.00

Republican primary edit

Candidates edit

Results edit

Republican primary results[1]
Party Candidate Votes %
Republican Robert D. Blue 102,246
Republican Henry W. Burma 63,011
Republican Milton W. Strickler 9,859
Total votes

General election edit

Candidates edit

Major party candidates

  • Robert D. Blue, Republican
  • Richard F. Mitchell, Democratic

Other candidates

  • Glen Williamson, Prohibition
  • Hugo Bockewitz, Socialist

Results edit

1944 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican Robert D. Blue 561,827 56.01%
Democratic Richard F. Mitchell 437,684 43.63%
Prohibition Glen Williamson 2,815 0.28%
Socialist Hugo Bockewitz 832 0.08%
Majority 124,143
Turnout
Republican hold Swing

References edit

  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1944. Retrieved April 14, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1944. Retrieved April 14, 2020.